The question is: Let $F(x) = f^2(g(x))$. If $g(1)= 2, g'(1)= 3, f(2) = 4$, and $f'(2) = 5$, find $F'(1)$.
$$ F'(x) = f'(f(g(x)) * (f \circ g)'(x) = f'(f(g(x)) * f'(g(x)) * g'(x)$$
put $1$ into $F'(x)$:
$$F'(1) = f'(f(g(1)) * f'(g(1)) * g'(1) = f'(f(2)) * f'(2) * 3 = f'(5) * 5 * 3$$
I can only solve the problem into this step. Is there any mistake I make? I cannot find a way to simplify the part of $f'(f(g(x))$. Thank you!
