Clearly, the only reason the function would be undefined would be a division by zero, i.e. as long as $x$ is not in $[-1,0)$, the function is defined.
Thus, the domain is
$$\{x:x<-1 \text{ or } x\geq 0\}.$$
Now, the function is constant on any interval of the form $[n,n+1)$, where $n\in\mathbb Z$ (although, again undefined when $n=-1$). Thus, one way to write the range is as
$$\{n\sin(\pi/(n+1)): n\in\mathbb Z \setminus \{-1\}\}.$$
I don't know that there is any easier way to describe the set, although we can certainly see some of it's characteristics. Using the fact that
$$\lim_{x\rightarrow 0} \frac{\sin(x)}{x} = 1,$$
it's not too hard to see that
$$\lim_{n\rightarrow \pm\infty} n\sin\left(\frac{\pi}{n+1}\right) = \pi.$$
Thus, $\pi$ is a cluster point of the range, while all other points are isolated. Beyond that, I think a graph is a reasonable thing to have. In the following picture, we see the graph together with a portion of the range plotted as red dots on the $y$-axis.

$$y=\left \lceil x \right \rceil.sin\frac{\pi}{\left \lceil x+1 \right \rceil}$$
– kryptoknight Aug 07 '13 at 13:44