I was solving the following question:
Find the period of $\min\{\sin x, |x|\}$.
My solution is: $\min\{\sin x, |x|\}=\sin x$. Hence period is $2\pi$.
Is my solution correct?
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1Seems correct to me. – Abezhiko Jan 07 '23 at 07:39
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2Yes , But prove min{sin(x),|x|)=sin(x) – Moustapha_M_I Jan 07 '23 at 07:45
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1$f(x)=x-\sin x$ is an increasing function for $x\geq 0$ as $f'(x)\geq 0$. Hence $\sin x\leq x$ – Learning Jan 07 '23 at 08:31