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I am reading through the chapter on iterated forcing from Halbeisen's set theory book and have some trouble about the notation that he uses.

Let $\mathbb{P}_{\alpha} = \langle \mathring{\mathbb{Q}}_{\gamma}: \gamma \in \alpha\rangle$ be an $\alpha$-stage iteration and let $G$ be $\mathbb{P}_{\alpha}$-generic over $\mathbf{V}$. Then, for $\beta \in \alpha$, he introduces the following objects:

\begin{equation*} G(\beta) = \{q_{\beta}: \exists \langle \mathring{p}_{\gamma}:\gamma \in \alpha\rangle \in \mathring{G}[q_{\beta} = \mathring{p}_{\beta}[G]]\} \end{equation*}

and \begin{equation*} G\vert_{\beta} = \{\langle q_{\gamma}: \gamma \in \beta\rangle: \exists \langle \mathring{p}_{\gamma}: \gamma \in \alpha\rangle \in \mathring{G}\forall \gamma \in \beta({q}_{\gamma}=\mathring{p}_{\gamma}[G])\}. \end{equation*}

He then claims, $G \vert_{\beta}$ is the $\mathbb{P}_{\beta}$-generic filter generated by $G$. Now, the definition must be wrong since $G \vert_{\beta}$ - as defined - is not even a subset of $\mathbb{P}_{\beta}$. Am I mistaken? If not, what are the correct definitions of $G\vert_{\beta}$ and $G(\beta)$?

  • Why isn't that a subset of $\mathbb{P}_\beta$? It looks like one to me. – Noah Schweber Jan 09 '23 at 05:42
  • I have several problems here: $\mathring{G}$is the canonical name of the $\mathbb{P}{\alpha}$-generic filter over $\mathbf{V}$ which is a set of ordered pairs, whereas $\langle \mathring{p}{\gamma}: \gamma \in \alpha\rangle$ is a sequence of names. Also $G \vert_{\beta}$ is a sequence of objects in $V[G]$ - not names. – user982056 Jan 09 '23 at 06:24

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