Let $p$ denote an odd prime power (a prime power is a number of the form $p^k$ where $p$ is a prime and $k \ge 1$). These are the numbers OEIS A061345 without the $1$.
For $p \ge 5$ defined prev$(p)$ to be the (strict) predecessor of $p$ in the set of odd prime powers, and gap$(p)$$\, =\, p\, - $ prev$(p)$ (by convention gap$(3)$$\, =\, 0$).
For example, if $p\, =\, 1361$ then prev$(p)$$\, =\, 1331$ and gap$(p)$$\, =\, 30$.
Conjecture: Let $p,\, q$ be odd prime powers. If gap$(p)$$\, > \, $gap$(q)$ for all $q < p$ then $p$ is prime.
Does anyone have an idea how to prove (or disprove) this?
Numerical verification confirmed the conjecture for numbers $\le 42652618807$. In this range all the potential candidates fulfilled the statement and identified this way 42 prime numbers.
Another observation is that the sum of the reciprocals seems to converge towards a value that starts $0.3141\ldots$