Can you explain to me why we're able to add the accumulated amount of 1000 invested for 5 years to the additional accumulated value of 1000 they invested after 3 years?
Asked
Active
Viewed 30 times
1
1 Answers
0
After $3$ years, there is
$$1000\cdot 1.01^{12}$$
in the account. Another $1000$ is deposited, and interest is applied for a further $2$ years:
$$\left(1000\cdot 1.01^{12}+1000\right)\cdot 1.01^{8}$$
This can be written as
$$1000\cdot 1.01^{12}\cdot 1.01^{8}+1000\cdot 1.01^{8}$$
$$=1000\cdot 1.01^{20}+1000\cdot 1.01^{8}$$
as in the solution.
JMP
- 21,771

Payment 1 is is made at $t=0$ and it is compounded five years. This is the future value of payment 2 at $t=5$.
Payment 2 is is made at $t=3$ and it is compounded two years ($=2\cdot 8$ quarters). This is the future value of payment 2 at $t=5$.
The sum is the future value of both payments at $t=5$
– callculus42 Feb 02 '23 at 18:31