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Does the ring extension $\mathbb{Z}\subset\mathbb{Z}[\frac{1}{10}]$ satisfy the going up property?

Going up property: For a ring extension $A\subset B$, if for any prime ideals $p\subset p'$ of $A$ and prime ideal $P$ in $B$ that lies over $p$, there is a prime ideal $P'$ in $B$ such that $P\subset P'$ and $P'$ lies over $p'$.

I know that a chain of prime ideals in $\mathbb{Z}$ is:

$$(0)\subset (p)$$ for primes $p\in\mathbb{Z}$ and a chain of prime ideals in $\mathbb{Z}[\frac{1}{10}]$ is:

$$(0)\subset (p)$$ for $p\in\mathbb{Z}$ except $p=2,5$.

Then clearly the going up property is satisfied for chains where $p\neq 2,5$. But I am confused if it has to also hold for the other chains as well. In other words, the going up property is said to be satisfied if it holds for all chains of prime ideals?

Could someone kindly clarify this?

Anish Ray
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