In AM, Artin-Rees lemma, there is no constraint on integer $k$ but in most sources, Artin-Rees lemma is stated: "there exists an integer $k>0$ s.t. ..." My question is: is $k=0$ not a possibility?
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@AlexWertheim The bracket is $(I^nM) \cap N = I^n(M \cap N)$. I can see the $\supseteq$ but how about the other way? – metalder9 Mar 08 '23 at 14:12
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My bad, I misread the statement of Artin-Rees. I'll delete my comment, sorry. – Alex Wertheim Mar 09 '23 at 04:13