I am having trouble with a math problem and I'm hoping someone can help me figure it out. The problem goes as follows:
"There are twelve dogs in a kennel drinking water from a large water tank. How many liters of water do the dogs drink in total during an average day?
(1) The dogs drink an average of 3 liters of water per dog per day. (2) The four smallest dogs drink an average of 2 liters of water per dog per day and the four largest dogs drink twice as much on average. Each of the remaining dogs drinks on average the same amount as the overall average for all the dogs in the kennel."
I tried to solve the problem by first calculating the total water consumption of the smallest and largest dogs, and then adding the consumption of the remaining dogs. Here's my attempt:
Let x be the overall average water consumption per dog per day.
The four smallest dogs consume 2 liters of water per dog per day, so their total water consumption is 4 * 2 = 8 liters.
The four largest dogs consume twice as much on average, so their total water consumption is 4 * 2 * 2 = 16 liters.
The remaining 4 dogs consume on average the same as the overall average, which is x. So their total water consumption is 4 * x = 4x liters.
Adding all these up, we get the total water consumption:
8 + 16 + 4x = 24 + 4x liters
However, I'm not sure where to go from here to get the final answer. Can someone please help me out?