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$\frac{dy}{dx}\ = \frac{-1}{x^3}\\$

is the solution:

$y = \frac{1}{2x^2} + k$

or

$y = \frac{1}{2x^2} - k$

number8
  • 515
  • $k$ is an arbitrary constant. If you wanted to signify an addition of $+5$, then you could choose $k=5$ in the first form, but you could also choose $k=-5$ in the second. Both are equally acceptable from a mathematical standpoint. However, because of human biases, we often prefer the $+C$, or, in your case, $+k$ formulation just to cut down on the number of minus signs. We're a pretty positive species, on the whole. – Deepak Mar 23 '23 at 00:10
  • I’m voting to close this question because it is trivial – Max0815 Mar 23 '23 at 16:35

1 Answers1

2

Both are correct, with the understanding that $k$ is an arbitrary constant.

Golden_Ratio
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