Let $(X,d)$ be a discrete metric space and $x \in X$. Describe the open ball $B(x,1)$ and the closed ball $B[x,r]$.
I understand the first ball. If distance is between $0$ and $1$ then we say that $y$ is any element of ball then $x=y$ .
I don't understand the second ball. When we think the same as like open ball ,then $x=y$ but it also can be $1$ so this cause $X$(the whole set).How to select which one is answer ? And how can it be whole set, is this whole set is just center which is radius 1 or different thing?
And a closed ball is a set $$\overline{B}(x,r)={y\in M : d(x,y)\leq r}$$
Split into four cases:
And think about how the open and closed balls will differ.
– K.defaoite Mar 31 '23 at 10:12