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Let $(X,d)$ be a discrete metric space and $x \in X$. Describe the open ball $B(x,1)$ and the closed ball $B[x,r]$.

I understand the first ball. If distance is between $0$ and $1$ then we say that $y$ is any element of ball then $x=y$ .

I don't understand the second ball. When we think the same as like open ball ,then $x=y$ but it also can be $1$ so this cause $X$(the whole set).How to select which one is answer ? And how can it be whole set, is this whole set is just center which is radius 1 or different thing?

K.defaoite
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1 Answers1

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For $0<r<1$ we have $B(x,r)=\{x\}$ and $B[x,r]=\{x\}$. Now for $r=1$ we have $B(x,r)=\{x\}$ and $B=[x,r]=X$. And finally for $r>1$ we have $B(x,r)=B[x,r]=X$.

gist076923
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