Take $y=ln(x^2)$, it's domain is all real x except 0. Now if we use the power law we end up with $y=2ln(x)$. And this functions domain is positive x. So what causes this change in domain?
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Another one: https://math.stackexchange.com/q/2023641/42969 – both found with Approach0 – Martin R Apr 14 '23 at 11:28
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This is because according to power law,
y= log(x^2)=2(log|x|)
So, if f(x)= 2(log(x)), log(x^2)=f|x| Hence, both are different functions and hence can have different domains.
Darsh Maheshwari
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