If $|z-5\sqrt3-5i|=5$, then find $a+b+c+d$ such that $\left|\frac1z-\frac1{a\sqrt{b}}+\frac{i}{c}\right|=\frac1d$.
I try to make the second equation look like the first one. Multiplying both sides by $acz\sqrt{b}$, we get $$|ac\sqrt{b} - cz + az\sqrt{b}i| = \frac{acz\sqrt{b}}{d}$$ Now we have $z$ in the numerator, which is good. Factoring $z$ out from the second and third terms in the "absolute value" signs, we get $$|z(-c + az\sqrt{b}i) + ac\sqrt{b}| = \frac{acz\sqrt{b}}{d}$$ Dividing both sides by $(-c + az\sqrt{b}i)$, we get $$\left|z + \frac{ac\sqrt{b}}{-c + az\sqrt{b}i}\right| = \left|z - \frac{ac\sqrt{b}}{c - az\sqrt{b}i}\right| = \frac{acz\sqrt{b}}{d(-c+az\sqrt{b}i)}$$ Looking at the 2 rightmost expressions, it resembles $|z - (5\sqrt{3} + 5i)| = 5$. We get $$\frac{ac\sqrt{b}}{c - az\sqrt{b}i}=5\sqrt{3}+5i$$ and$$\frac{ac\sqrt{b} \cdot z}{(-c+az\sqrt{b}i) \cdot d} = 5$$ Dividing the equations gives $\frac{d}{z} = \sqrt{3} + i$.
But then I don't know how to combine $\frac{d}{z}=\sqrt{3}+i$ and $\frac{ac\sqrt{b}}{c - az\sqrt{b}i}=5\sqrt{3}+5i$ to find $a + b + c + d$.
Note: Please do not provide any answers using material beyond Algebra 2.