Regarding the quadrature of the parabola:
In a parabolic segment (the area enclosed by a parabola and a chord that intersects it), the vertex is defined as that point on the parabola which is "perpendicularly" furthest away from the chord. (That is, of all the lines perpendicular to the chord that intersect with the parabola, the intersection point of the longest line is the vertex).
I have read that in the time of Archimedes, it was known that the tangent line to the parabola at the vertex point is parallel to the chord.
If you sketch out a parabolic segment, this seems intuitively true - the only tangent to the parabola that you can draw that's parallel to the chord is indeed the one located at the point furthest away (perpendicularly) from the chord.
However, I can't figure out how to demonstrate the truth of this assertion. I would really like to know how to prove it - without resorting to calculus (which of course wasn't available back then).
Thank you!
