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I want to proof:

"Let $(L,[\cdot,\cdot])$ be a (right or left) Leibniz algebra. If $[L,L]$ is nilpotent then $L$ is solvable".

I know that a similar result is posted for Lie algebras. But here we get a more general context with the Leibniz algebras.

Thanks in advance!

LH8
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1 Answers1

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This is only true for finite-dimensional algebras over a field of characteristic zero. It follows from a weak version of Lie's Theorem for Leibniz algebras, see Corollary $6$ in the paper On some basic properties of Leibniz algebras by V. Gorbatsevich.

Dietrich Burde
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