How can I solve this integral containing inverse cosh? Does it have any antiderivative?
$$ \int_b^r t^2 \operatorname{arccosh}(a/t) \sqrt{r^2 - t^2} d t$$
for $0< b< r< a$.
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I have found the antiderivative and the integral if t^2 is replaced by t – Billo Aug 23 '13 at 11:00
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I tried to fix the latex. Please do not copy paste mathwolfram commands here. – Marc Palm Aug 23 '13 at 11:03
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Only for ${a,r}\subseteq{0,1}$ apparently. And even then it looks hideous. – Lucian Nov 17 '13 at 22:47