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enter image description here

Any tips how to proceed? It's for sure that Ac is the radius but what next?

mathphy
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3 Answers3

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Hint: $AC=AB=BC$, hence $ABC$ is an equilateral triangle.

4

Hint: AB and BC are also radii.

njguliyev
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Since the circles have the same radius, $$ AC = AB = \text{radius of circle 1} = \text{radius of circle 2} = CA = CB $$

Now consider the triangle $ ACB$.

Parth Thakkar
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  • No need to say "Assuming"! They have the same radius. – Ted Shifrin Aug 24 '13 at 17:51
  • I thought of that, and that's quite obvious from the figure and the fact that nothing is said about it - but then...there's always an element of doubt. I mean, that was typed just like that. I'll edit it if you say :D – Parth Thakkar Aug 24 '13 at 17:53
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    I agree one can't assume anything from a figure. But we are told that $A$ and $C$ are the centers, so $\overline{AC}$ is a radius of both circles. :) – Ted Shifrin Aug 24 '13 at 17:55
  • Ah damn! That I didn't even think. Removing the strikethrough too. Thanks for pointing it out – Parth Thakkar Aug 24 '13 at 17:56