percentage increase in performance

Question

What is :

by how much
to how much

efficiency of algorithm is increased , if

Initially it was executing in 20 seconds, after improvement (Final Time) it is executing only in 5 seconds. My Try:

1. by how much : (Initial Time - Final Time)
                 --------------------------- * 100
                    Initial Time  
2. to how much : Initial Time
                 ------------- * 100
                  Final Time

tell me if i'm wrong?

amWhy · Accepted Answer · 2013-08-25T17:55:22.880

3

You've got the right idea, and perhaps I'm splitting hairs, but I think we could also swap the equations:

That is, the improvement increases performance by $$\frac{\text{initial time}}{\text{final time}}\times 100\% = 400\%.$$

The change leads to a $$ \frac{\text{initial time} - \text{final time}}{\text{initial time}}\times 100\% = 75\%$$ improvement in performance.

(perhaps you can clarify exactly how "by" and "to" are to be understood)

edited Aug 25 '13 at 17:55

answered Aug 25 '13 at 17:47

amWhy

209,954

yes , I think you are correct. – sourcecode Aug 25 '13 at 17:59
Glad to help. I understand, completely. I've been known to "overthink" problems, myself. – amWhy Aug 25 '13 at 18:00
@amWhy: Needs to TU to go with check. :-) =1 – Amzoti Aug 26 '13 at 01:02

percentage increase in performance

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