$\sqrt [ 3 ]{\frac{3}{4} }$ is the expression. What i did was change it to an equivalent fraction $({\sqrt [ 3 ]{\frac{6}{8} }=\frac{\sqrt [ 3 ]{ 6}}{2} } )$. But i think it isn't right. Please help me.
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jaseem
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ikaidubidu
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So what did you do exactly? – imranfat Aug 26 '13 at 15:05
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i chaged it to 3/4 to 6/8 to get a perfect cube, my answer is cube root of 6/2. is it right? – ikaidubidu Aug 26 '13 at 15:07
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You phrased it wrong but I think you are correct. It's the cube root of 6 and that quantity divided by 2 – imranfat Aug 26 '13 at 15:12
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1As LaTeX'ed, looks perfectly good. Right strategy, right result. – André Nicolas Aug 26 '13 at 15:20
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If you did this, you were correct (writing out every possible step):
$$\sqrt[3]{\frac{3}{4}} =\sqrt[3]{\frac{2\times 3}{2\times 4}} =\sqrt[3]{\frac{6}{8}} =\frac{\sqrt[3]{6}}{\sqrt[3]{8}} =\frac{\sqrt[3]{6}}{2} $$
marty cohen
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