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This is related to this Nice answer by the thread

What is the Fourier transform of $f(x)=e^{-x^2}$?.

Considering this derivation of fourier transform of Gaussian with mean 0 and unit variance, why do we get complex data type when I take fourier transform of AWGN (Addititive white gaussian noise) ?. (You can try in matlab by taking FFT of awgn function.)

"""

no_sig = zeros(128,256);

no_sig_noise = awgn(no_sig,0);

no_sig_fft = fft2(no_sig_noise);

"""

if you observe no_sig_fft, it has complex form (a+jb). My question is : As per the derivation, the Fourier transform of Gaussian distributed data is : $e^{-w^2/4}$ , which will give real data. But when i do fft of AWGN, i get complex data ($a+jb$). Why is this so. Anything i have missed in understanding?

Vinay
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  • Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking. – Community Oct 12 '23 at 08:19
  • please see if this clarifies my question. – Vinay Oct 13 '23 at 07:39

0 Answers0