This is a problem of choosing the correct statement.
In a certain class of a school, we have investigated whether each student likes candy, pizza, chocolate, and egg. Then, from the result, we know
・ all students that like candy like egg
・ all students that like chocolate don't like egg
・ all students that don't like chocolate like pizza
・ there is no student who likes all four kinds of food.
Then, choose what we can say.
There is(are) a(some) student(s) who like(s) pizza and chocolate.
There is(are) a(some) student(s) who like(s) only chocolate, i.e., like chocolate but don't like other food.
There is no student who likes three kinds of food.
I want to find the answer by using logic.
Let me regard $Ca$ as "like candy" and $\overline {Ca}$ as "don't like candy", and so on. (pizza : $P$, chocolate : $Ch$, egg : $E$)
Then, we know
・$Ca \implies E$
・$Ch \implies \overline E$
・$Ch\implies P$
・$\forall x\in [this\ class]$, $x\in (Ca)^c\cup P^c\cup (Ch)^c\cup E^c$
Now, since the class is not empty, there is some student $x.$ Then, from the fourth condition, $x\in (Ca)^c\cup P^c\cup (Ch)^c\cup E^c.$
・If $x\in (Ca)^c$, then I think there is nothing we can say from other conditions.
・If $x\in P^c$, then $x\in (Ch)^c$ from the third condition.
・If $x\in (Ch)^c$, then there is nothing to say.
・If $x\in E^c$, then $x\in (Ca)^c$.
I cannot proceed from here and cannot find the correct statement from 1-3. Is it difficult to solve this problem by using logic ?
I'd appreciate any idea.
Add:
The answer is 2. However, if so, I think the additional condition is needed : [there is at least one student that likes chocolate ($Ch\neq\emptyset$).]

