Good day! Can someone help me with a math problem?
Boxes X, Y, and Z contain 14.7 liters of water in total.
2/7 of the water in Box X is poured into Box Y.
Then, 1/3 of the water in Box Y is poured into Box Z.
After that, the volume of water in each box was the same.
a) Find the volume of water in each box in the end.
b) Find the volume of water in Box Y at first.
What I can worked out is only:
a) Find the volume of water in each box in the end.
It's actually 14.7 / 3 = 4.9
b) Find the volume of water in Box Y at first.
X + Y + Z = 14.7
X after poured: 1 - 2/7 X = 5/7 X
Y after poured: (Y + 2/7 X) - 1/3 Y
5/7 X = (Y + 2/7 X) - 1/3 Y = 4.9
5/7 X = 14.7 / 3 = 4.9
X = 4.9 * 7 /5 = 6.86
5/7 * 6.86 = (Y + 2/7 * 6.86) - 1/3 Y = 4.9
(Y + 2/7 * 6.86) - 1/3 Y = 4.9
2/3 Y + 1.96 = 4.9
Y = 4.41
Am I getting it right? Thank you.
1/3 Y, but should be $1/3$ of the total, including some water from Box X at first. – peterwhy Nov 01 '23 at 04:55