In the way in which $x^{x^{x^{x}}}$ can be written as $x$ tetrated to 4 is there such a method to writing $\sqrt[...\sqrt{2}]{2}$ extending out to the left.
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You mean like $\sqrt{\sqrt{\sqrt{x}}}$? – Ninad Munshi Nov 23 '23 at 00:31
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2No, like $2^{\frac1{2^{\frac1{2^{\frac1\dots}}}}}$ – Karl Nov 23 '23 at 00:33
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Yeah I intended it to be in the way in which karl stated – MrMez Nov 23 '23 at 21:39