I can't see what to do in the two STEP level questions below. Can anyone give me a clue, please?
The function $f$ satisfies the condition $f'(x) > 0$ for $a \leq x \leq b$, and $g$ is the inverse of $f$.
By making a suitable change of variable, prove that $$\int_{a}^{b} f(x) \, dx = b\beta - a\alpha - \int_\alpha^\beta g(y) \, dy$$ where $\alpha = f(a)$ and $\beta = f(b)$. Interpret this formula geometrically, in the case where $\alpha$ and $a$ are both positive.
Prove similarly and interpret (for $\alpha > 0$ and $a > 0$) the formula $$2\pi\int_{a}^{b} xf(x) \, dx = \pi(b^2\beta - a^2\alpha) - \pi\int_\alpha^\beta [g(y)]^2 \, dy.$$
This is the simplest situation I can come up with but something does not add up.
