Here $(\mathbb{R},d)$ is metric space with usual distance metric and $(\mathbb{R},d')$ is metric with discrete metric. I think there is no this type of set in $(\mathbb{R},d)$ which is not open in $(\mathbb{R},d')$.
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2Of course, since in $(\Bbb R,d')$ every subset is open. – José Carlos Santos Dec 08 '23 at 17:25
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Every singleton set is open in $(\mathbb{R},d^\prime)$, the discrete metric space. That is because the balls of radii $< 1$ are all singletons. Since every open set in $(\mathbb{R},d)$ can be expressed as a union of singleton sets, then it is an open set in $(\mathbb{R},d^\prime)$.
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