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If we push a box (mass of 2 kilograms) with a force of 4 newton, how we can find the velocity at t= 0 after pushing the box?

i tried: a=f/M; then with integration => v(t) - v(0) = f/m * t; => v(0) = f/m * t +v(t), but we can't here

Aymen
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1 Answers1

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We know $\text{Force}= \text{Mass}\times\text{Acceleration}$

The formula for acceleration is:

$\text{Acceleration} = \dfrac{\text {Force}}{\text{Mass}}$

So, $\text{Acceleration}= \dfrac 42 N = 2N$

Acceleration gives the rate of change of velocity over time. If the box starts from rest $t = 0$, the velocity at $t = 0$ can be calculated using the equation of motion that relates acceleration, initial velocity, time, and displacement:

$\text{Final velocity} = \text{Initial velocity} + \text{Acceleration}\times\text{Time}$

Assuming that the box starts from rest, i.e. $v = 0$:

$\text{Final velocity}= 0 + 2\cdot 0 = 0 m/s$

So, at $t = 0$, the velocity of the box after applying the force is $0$ m/s if it started from rest.

If it does not start from the rest: Without information about the initial velocity of the box or the duration of the applied force, it’s not possible to calculate the velocity of the box at a time after $t=0.$ If the box starts from rest, then its velocity at $t=0$ would be $0$ m/s. But in this case, as you mentioned, the box does not start from rest. Therefore, more information is needed to provide a precise answer.

Divide1918
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Samin Mustakim
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  • yes, but that's not what i want, u calculate the velocity at the rest, but i want the velocity at the hitting time which is the maximum velocity then the velocity start decreasing because the friction. – Aymen Dec 29 '23 at 11:12
  • Without information about the initial velocity of the box or the duration of the applied force, it’s not possible to calculate the velocity of the box at a time after t=0. If the box starts from rest, then its velocity at t=0 would be 0 m/s. But in this case, as you mentioned, the box does not start from rest. Therefore, more information is needed to provide a precise answer. – Samin Mustakim Dec 29 '23 at 11:20
  • the initial velocity is 0, but what do u mean but duration of the applied force, why the force = 4Nis not enough, what if the 4N force was from another box to make collision, here there is no duration of the applied force. – Aymen Dec 29 '23 at 11:29
  • I want to said that there is no information of the past before applying the force. If you give information of the force that was applied before t(0) the problem can be solved. Without that, it's impossible to solve for not starting from the rest. – Samin Mustakim Dec 29 '23 at 11:35
  • what is the required information to find v after hiting the box, (the box was at rest). – Aymen Dec 29 '23 at 13:33
  • if the box was at rest then my solution will work that is mentioned upward – Samin Mustakim Dec 29 '23 at 13:34
  • i mean the v max, the v max is not 0. – Aymen Dec 29 '23 at 13:37
  • there is no velocity in t=0. In rest t=0 means v=0 too – Samin Mustakim Dec 29 '23 at 13:41
  • but there is a maximum velocity the box can reach before it starts decreasing to 0 again, i want to find the maximum velocity and, this can't be 0. i hope u understand what i want to find. – Aymen Dec 29 '23 at 13:49
  • its 0 (zero). how can this be possible? – Samin Mustakim Dec 29 '23 at 13:55
  • This is impossible to be 0(zero) because we know that the box changed its position, so it got some speed to change its position. – Aymen Dec 29 '23 at 14:02
  • but you said that t=0 – Samin Mustakim Dec 29 '23 at 14:08
  • Sorry, by t=0 I meant the time at which the speed is maximum – Aymen Dec 29 '23 at 14:12
  • I misunderstood you, i thought it was zero – Samin Mustakim Dec 29 '23 at 14:16
  • so, you know how to solve find the maximum velocity? – Aymen Dec 29 '23 at 14:40
  • Let us continue this discussion in chat. – Aymen Dec 29 '23 at 17:21