I need solve the given integral: $$\int\sqrt[4]{4x-x^4}dx$$ My attemp: $$\int\sqrt[4]{4x-x^4}dx=\int x^{\frac{1}{4}}(-x^3+4)^{\frac{1}{4}}dx$$ $p=\frac{1}{4}, q=4, r=\frac{1}{4}, s=2.$ $\frac{p+1}{q}, and \frac{p+1}{q}+r$ is not integer. I have treated it as the integral of the binomial differential, but neither of the two conditions is fulfilled, so I don't know how to proceed, can anyone help me
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2The first step seems to add a power of $x$ inside the root... Shouldn't it be $-x^3$? – abiessu Jan 02 '24 at 15:55