0

$$\theta = \tan^{-1} \left( \frac{\frac{\nu^2}{rg} - \mu}{1 + \frac{\mu \nu^2}{rg}} \right)$$

I entered the formula above into a python code and ran it to:

Starting at 1, increase the velocity and radius by 1 and give out an answer for each iteration.

I found that past a certain point the angle gets to 73 or 74 degrees and doesn't increase much further than this.

Graph

Is there a reason for this?

Robin
  • 3,227
Diar Tylr
  • 1
  • The limiting angle depends on the value of $\mu$. As $v\to\infty$ (and I guess you're having $r\to\infty$ also, with $r=v$), the quantity inside the fraction approaches $1/\mu$, so $\theta$ approaches $\tan^{-1}(1/\mu)$. – Ted Shifrin Jan 13 '24 at 18:38

0 Answers0