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I'm trying to teach myself simple electronic formulas. I haven't done algebra in awhile, and I'm very rusty.

I know that $P = iV$, and $V = iR$, therefore, $P = i^2R$.

How could I figure out that $P = V^2 \div R$, because I know $P = i^2R$?

Is there a name for the trick used? I would like to find out more about it.

LuminousNutria
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    $$i = \dfrac{P}{V}, i = \dfrac{V}{R}$$ So $$\dfrac{P}{V} = \dfrac{V}{R}$$ Can you continue? – Moo Jan 15 '24 at 22:31
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    To the extent that there's a 'name' for this, it's that you're eliminating $i$ in favor of $V$. (Whereas in your original work you eliminated $V$ in favor of $i$.) But it's such a standard operation that one usually doesn't name it. – Semiclassical Jan 15 '24 at 22:34
  • @Moo thanks! I can see that $P = (V \div R) ^2 R = V^2 \div R$ now. – LuminousNutria Jan 15 '24 at 22:35

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I realized that since current equals voltage divided by resistance, IE $i=V \div R$.

$P=i^2R = (V \div R)^2 R = V^2\div R$

LuminousNutria
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