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I found a interesting question in one exam.

If 5 < x < 10 and y = x + 5, what is the greatest possible integer value of x + y ?

(A) 18
(B) 20
(C) 23
(D) 24
(E) 25

MySol: For max value of x+y , x should be 9. So x+y = 9+14 = 23

But this is not correct. Can someone explain.

vikiiii
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3 Answers3

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Note that $x+y=2x+5$. The greatest possible integer value of $2x$ occurs at $x=9.5$.

Remark: Unfortunately, a bit of a trick question. Not nice! One of my many objections to multiple choice questions is that they are too often designed to fool people into giving the "wrong" answer.

André Nicolas
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  • What do you mean by not nice? – vikiiii Sep 06 '13 at 18:47
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    I mean it is not a nice qustion to ask, since the main intent seems to be to get people to choose $23$. – André Nicolas Sep 06 '13 at 18:48
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    There's ambiguity on what number system to use for x and y. If x and y are integers then 23 is correct, however if rationals are allowed then 24 is the answer. – JB King Sep 06 '13 at 19:45
  • I did the problem in my head and came up with 24 by mistake. – Michael Sep 06 '13 at 21:05
  • All standardized tests that I know of state in the introduction of every math section that all variables represent Real numbers unless otherwise stated, so there is no actual ambiguity if you understand the rules. Also, standardized tests are not subject tests, they are reasoning tests; this is a very good reasoning question: "Do you actually think about all of the facets or jump to easy conclusions?" – John Sep 06 '13 at 23:42
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$x<10\implies y=x+5<15\implies x+y<10+15=25$

If $x+y$ has to be integer, $ x+y\le24$

Observe that the equality occurs if $x+y=24 \iff x+(x+5)=24\iff x=\frac{24-5}2=9.5$

i.e., $x,y$ are individually non-integer unlike your assumption

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$x+y = x+x+5 = 2x + 5$ and since $5<x<10$, we have $15<2x+5<25$.

Alraxite
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