Quadrilateral ABCD is inscribed in a circle and its diagonals AC and DB intersect at P. If AB = 5, BP = 2 and CD = 6 find CP.

Asked Mar 12 '24 at 10:35

Active Mar 28 '24 at 21:54

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I arrived at the answer CP = 12/5 units. Since ∆APB — ∆DPC. So there ratio is BP/CP = AB/DC, 2/CP = 5/6, 1/CP = 5/12, CP = 12/5.

Is this correct way to solve?

edited Mar 28 '24 at 21:54

amWhy

asked Mar 12 '24 at 10:35

Yang

Yes it's all fine. What made you doubt your solution? – Sisanta Chhatoi Mar 12 '24 at 12:01
My teacher arrived at a different answer, so I have doubts about this question. I also have another question for her about a different problem, and I am confident that I am also correct. – Yang Mar 13 '24 at 08:58

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