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I recently saw this question and wanted to generalize it to $\mathbb{Z}^n$ and matrices with integer coefficients. I think $k\mathbb{Z}^n$ is a submodule for any integer $k$. Is there a nice way to generalize this?

Alex Wertheim
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1 Answers1

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All submodules of $\mathbb{Z}^n$ are of the form $k\mathbb{Z}^n$. Namely, if $S$ is a nonzero submodule then $S = d\mathbb{Z}^n$, where $d$ is the gcd of all integers which appear as entries of elements of $S$. This can be seen by repeated application of Bézout's identity.