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What is the x-intercept of $|x-12|+8$? I don't know how to solve it with the absolute values and whether there will be two answers.

user93089
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Jess
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1 Answers1

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It doesn't have one, for if $|x - 12| + 8 = 0$, then $|x - 12| = -8 < 0$, which isn't possible.