What is $\mathbf{a}^\bot=(\alpha, \beta)^\bot=(\beta, -\alpha)$ notation?

Question

I stumbled upon this notation in a book and I cannot find a reference on what this can mean: $\mathbf{a}^\bot=(\alpha, \beta)^\bot=(\beta, -\alpha)$

Here is where I found it:

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@MichaelAlbanese, added the original fragment of a book, check it out — Trident D'Gao, Sep 21 '13 at 02:25

score 2 · Accepted Answer · answered Sep 21 '13 at 02:28

2

Presumably, $\vec{a}^{\perp}$ is the vector that is orthonormal to $\vec{a}$ with the same norm. Note that $\vec{a}\cdot \vec{a}^{\perp} = 0$ and $||\vec{a}^{\perp}|| = ||\vec{a}||$.

answered Sep 21 '13 at 02:28

Cameron Williams

29,432

What is $\mathbf{a}^\bot=(\alpha, \beta)^\bot=(\beta, -\alpha)$ notation?

1 Answers1