How to find a birational transformation that turns the equation $3(y^2-1)=2x^2(x^2-1)$ into Weierstrass form? Thanks!
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First you can expand all terms and divide by $3$ to get
$$ y^2 = \frac{2}{3}x^4-\frac{2}{3}+1 $$
Then you can readily apply Theorem 6 from
http://homepage.uconn.edu/alozano/info/constrECrank_ALM.pdf
to get
$$ v^2 = u^3 - \frac{2}{3}u^2 - \frac{8}{3}u + \frac{16}{9} $$
with
$$ u = \frac{2(x-\frac{2}{3})}{y}, v = -1+\frac{u^2x}{2} $$
According to Sage the elliptic curve has rank $2$ and $2$ torsion points.
Jesper Petersen
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The link is broken. – KCd Jun 09 '14 at 21:56
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The article has moved to here: http://alozano.clas.uconn.edu/wp-content/uploads/sites/490/2014/01/constrECrank_ALM.pdf – Jesper Petersen Jul 05 '14 at 07:01