The operators represent the translations relative to an initial starting position $1234$. If you want to apply it successively, you have to suppose that the numbers in the operators are not the numbers in what's currently displayed. You could use letters to represent the starting point, like $abcd$.
In any case, $(1,2)(3,4) \cdot 1,2,3,4$ gives $2,1,4,3$. Applying $(1,2,3) \cdot 2,1,4,3$ rotates the first three elements, to give $1,4,2,3$.
You can directly derive $1,4,2,3$ from $1,2,3,4$ by rotating the triplet $2,3,4$, ie $(2,3,4)$
So the operation $(1,2,3) \cdot (1,2)(3,4) = (2,3,4)$
(34)means send 3 to 4 and 4 to 3.(12)means sending 1 to 2 and 2 to 1.(123)means sending 1 to 2 and 2 to 3 and 3 to 1. So, what happens if you apply all three in turn (first applying34, then12, then123)? Well, you have to see where each individual number will be sent. For example, 1 will first be sent to 2, and then it will be sent to 3 by the third permutation (since it is now a 2). Thus the final permutation should send 1 to 3. – Caleb Stanford Sep 28 '13 at 08:25