Chebyshev method $$ (1)\space\space p_{n+1}=p_n-\frac{f(p_n)}{f'(p_n)}-\frac{1}{2}\frac{[f(p_n)]^2f''(p_n)}{[f'(p_n)]^3} $$ Halley method $$ (2)\space\space p_{n+1}=p_n-\frac{f(p_n)}{f'(p_n)-\frac{f(p_n)f''(p_n)}{2f'(p_n)}} $$
First we know that Newton method is $$ (3)\space\space p_{n+1}=p_n-\frac{f(p_n)}{f'(p_n)}\to{p_{n+1}-p_n=\frac{-f(p_n)}{f'(p_n)}} $$ And the second order Taylor series expanded about $p_n$ says $$ (4)\space\space f(p_{n+1})=f(p_n)+f'(p_n)(p_{n+1}-p_n)+\frac{1}{2}f''(p_n)(p_{n+1}-p_n)^2=0 $$ We write $(4)$ as $$ (5)\space\space p_{n+1}=p_n-\frac{f(p_n)}{f'(p_n)}-\frac{1}{2}\frac{f''(p_n)}{f'(p_n)}(p_{n+1}-p_n)^2 $$ Substituting the value of $p_{n+1}–p_n$ from $(3)$ by $\frac{-f(p_n)}{f'(p_n)}$ on the right side of $(5)$ we get Chebyshev method. Also we can write $(4)$ as $$ (6)\space\space p_{n+1}=p_n-\frac{f(p_n)}{f'(p_n)+\frac{1}{2}f''(p_n)(p_{n+1}-p_n)} $$ Again we use $(3)$ to obtain Halley method. Is there any difference or I am so stupid?!