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Consider the upper traingular $N \times N$ matrix

$$\left(\begin{array}{cccccccc} 0 & b_{1} & \dots & b_{q} & 0 & 0 & \dots & 0\\ \vdots & 0 & b_{1} & \dots & b_{q} & 0 & \dots & 0\\ \vdots & & \ddots & & & & & \vdots\\ \vdots & & & 0 & b_{1} & \dots & b_{q} & 0\\ \vdots & & & & 0 & b_{1} & \dots & b_{q}\\ \vdots & & & & & 0 & \dots & 0\\ \vdots & & & & & & \ddots & \vdots\\ 0 & \dots & \dots & \dots & \dots & \dots & \dots & 0 \end{array}\right)$$

Is there a name for matrices of this form?

rwolst
  • 741

3 Answers3

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The upper block has several properties that you can combine in a name:

strictly upper triangular, Toeplitz, band matrix with a right/upper bandwidth $q$.

However, if you want to describe the whole matrix, you lose the "Toeplitz" part. You might say

These matrices are of form

$$\begin{bmatrix} X \\ 0 \end{bmatrix}$$

where $0$ is a zero matrix of order $q \times n$, and $X$ is strictly upper triangular, Toeplitz, band matrix of order $(n-q) \times q$ with a right/upper bandwidth $q$.

However, I believe a formal, nameless description is far better.

Vedran Šego
  • 11,372
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There is, so far as I know, no standard name for this type of matrix. However, it is composed of the first $q$ superdiagonals of the matrix, so "q-superdiagonal matrix" might be a sensible thing to call them.

0

Strictly (zeros on the diagonal) upper triangular (obvious) banded (has a limited band) Toeplitz (is a diagonal-constant) matrix.

You can call it a StrUTriBaToM :-)