Actuarial Science FM Question

Question

$$a(t)=Zt^2+Bt+1$$

If \$100 at $t=0$ grows to \$152 at $t=4$ and \$200 at $t=0$ grows to \$240 at $t=2$, what are $Z$ and $B$? Please show work. Also, what would \$1600 invested at $t=6$ grow to at $t=8$?

Can you share your thoughts on the problem, and explain what you've tried and what's giving you trouble? — , Oct 04 '13 at 05:11
My trouble is that I am not sure how to go about solving for Z and B. I know how to apply the function but I am unable to figure out the two unknown variables. — steven, Oct 04 '13 at 05:14
a(t) is an accumulation function that when t=0 the value of the function is equal to 1. — steven, Oct 04 '13 at 05:47

Tyler · Answer 1 · 2014-09-02T17:58:27.437

3

Since $\$ 100$ grows to $\$152$ from time $t=0$ to $t=4$, we know that $a(4) = 1.52$. Likewise, we know from the information about the $\$ 200$ investment that $a(2) = 1.2$. This is simply using the definition of the accumulation function.

Now, we have two equations and two unknowns:

$a(2) = 1.2 = 2^2 Z + 2B + 1$

$a(4) = 1.52 = 4^2 Z+4B+1$

Solve these equations using elimination or substitution.

Let me know if you need more help.

edited Sep 02 '14 at 17:58

answered Oct 15 '13 at 01:40

Tyler

2,857

This helped me tremendously. You plugged in the wrong values for t, but I was still able to figure everything out from there. Thank you good sir! – user146925 Sep 02 '14 at 15:48
@user146925 how embarassing! I'll fix it in a moment. thanks for pointing that out. – Tyler Sep 02 '14 at 17:03

score 0 · Answer 2 · answered Feb 09 '14 at 16:23

Part A

$\bullet$ consider the amount function $a(t)=\dfrac{A(t)}{A(0)}$,

$\bullet$ use the information given as follows to solve for $Z$ and $B$

$A(0)=100,A(4)=152$

and

$A(0)=200,A(2)=240$

Part B

for an amount invested at $s>0$ the value of the investment at $t>s$ is

$A(t)=A(s)\dfrac{a(t)}{a(s)}$

with $s=6,t=8$

$A(8)=1600\dfrac{a(8)}{a(6)}$

Actuarial Science FM Question

2 Answers2