A is a 3 × 3 matrix with entries from the set {–1, 0, 1}. Then the probability that A is neither symmetric nor skew-symmetric is:
My thoughts: There can be nine members on a $3*3$ matrix and there are three possibilities for each member. Therefore the total no. of matrices possible is $3^9$. Subtracting the no. of possibilities for skew symmetric and symmetric matrices from it and dividing by $3^9$ will give the required probability but, I'm not able to figure out the values to be subtracted. Is there a relationship between the total number of possibilities and the number of possibilities for symmetric or skew-symmetric matrix.
Please help and thanks in advance.