How many different three digit numbers can be formed with the digit $1,2,3,4,5,6,7,8$ none of the digit being repeated in any of the numbers so formed? $120/1200/180/270$
My attempt: $8*7*6=336$, but it's not an option. I wish somebody could help.
How many different three digit numbers can be formed with the digit $1,2,3,4,5,6,7,8$ none of the digit being repeated in any of the numbers so formed? $120/1200/180/270$
My attempt: $8*7*6=336$, but it's not an option. I wish somebody could help.