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We have $\Pi_{j=1}^n (z-z_j)$ a polynomial with integer coefficients. Is also $\Pi_{j=1}^n (z-z_j^k)$ for k=1,2,3,... a polynomial with integer coefficients?

Marko
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1 Answers1

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Yes. The coefficients of the latter are symmetric polynomials in the $z_j$, hence are (integer!) polynomials in the elementary symmetric polynomials in the $z_j$, that is in the coefficients of the former polynomial.