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If $|z| = 2$. Then Locus of $z$ Representing The Complex no. $-1+5z,$ is

$\underline{\bf{My\;\; Try::}}$ Let $z^{'} = -1+5z$, Where $z^{'} = x^{'}+iy^{'}$. So put $5z = z^{'}+1$ in $|z| = 2\Leftrightarrow |5z| = 10$

$|z^{'}-(-1+0\cdot i)| = 10$, means Locus of Conplex no. $z^{'}$ is a Circle with Center at $(-1,0)$

and Radious $ = 10$

Is it Right OR Not, If Not . The please explain me Righta answer.

juantheron
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1 Answers1

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Well done! Your reasoning is spot on!

Cameron Buie
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