In class, my math teacher was teaching us how to draw functions on a coordinate plane, and he mentioned something about the Y-Intercept being an important step in creating/solving a function. But, what exactly is a Y-Intercept?
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It's where the function intersects the $y$-axis. I.e. where $x = 0$. – Daniel Donnelly Oct 15 '13 at 22:26
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The function intersects the $y$-axis as a subset of points of $\mathbb{R}^2$. Say if $f : \mathbb{R} \to $ itself. The graph of $f$ is ${(x, f(x)) : x \in \mathbb{R} }$ and the $y$-axis is defined as the subset ${(0, y) : y \in \mathbb{R} }$. Intersect the two sets. Since $f$ is a function, by definition there is one and only one point in the intersection. – Daniel Donnelly Oct 15 '13 at 22:28
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The $y$-intercept of a function $f(x)$ is the point where the function intersects the $y$-axis (if in fact it does intersect the $y$-axis) and it is found by evaluating $f(0)$, i.e., finding the value of $f(x)$ when $x = 0$.
For example,
the line $f(x) = y = 3x + 2$ intersects the $x$-axis at when $x = 0$:
when $\;y = 3\cdot 0 + 2 = 2$. This is the function's y-intercept.The parabola $f(x) = y = 2x^2 + 8$ intersects the $y$-axis when $x = 0:\;$
when $\;y = 2(0)^2 + 8 = 8$. This is the function's y-intercept.
amWhy
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So you are saying that the Y axis is the point where the function intersects with the Y axis? – Scribblenautical Oct 15 '13 at 22:31
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Yes, the y-intercept is the point where the function intersects the y-axis. To find it, just plug in $x = 0$ into the function, since $x = 0$ exactly at the y-axis. – amWhy Oct 16 '13 at 00:02
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