Given a point $P = (x_P, y_P)$ and a function $f(x)$, how can I find the set of all points $Q\in f$ such that the periphery of the osculating circle to $f$ in $Q$ goes through $P$? Is there a curve for which every osculating circle goes through $P$?
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Check out this wiki. – Lays Oct 16 '13 at 18:40
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@Lays I couldn't find an answer to my question on the page you linked. Please note, that $P$ usually does not lay on $f$. – FUZxxl Oct 16 '13 at 18:53