I faced a problem to understand the proof of the following theorem from the book "algebraic topology by satya deo".
If $F\colon X\to Y$ be a homotopy between two maps $ f,g\colon X\to Y $. Let $x_0\in X$ and $\sigma\colon I\to Y$ be the path joining $f(x_0)$ and $g(x_0)$ defined by $\sigma(t)=F(x_0,t)$. Then the triangle of induced homomorphisms is commutative i.e. ($\sigma_\#)\circ(f_\#)=g_\#$.
Also, if $f\colon X\to Y$ is homotopic to a constant map $C\colon X\to Y$,then the induced homomorphism $f_\#\colon\pi_1(X,x_0)\to \pi_1(Y,f(x_0))$ is the zero map.
proof:-
first part
Here I have only one problem in the first line of the theorem as author writes
Let $\alpha$ be a loop in $X$ based at $X_0$.then we know that
$$(\sigma_\#)\circ(f_\#)[\alpha]=\sigma_\#[f\circ\alpha] \\
=[\sigma^{-1}*(f\circ\alpha)*\sigma ]$$
My question is how did he write $\sigma _\#[f\circ\alpha] =[\sigma^{-1}*(f\circ \alpha) * \sigma] $ in the 2nd line instead of $[\sigma \circ f\circ\alpha]$ what he has done in the first line.
Can someone explain me please how did this happen.
second part
here he writes that "in the commutative triangle $\sigma_\#$ is isomorphism and $C_\#\colon\pi_1(X,x_0)\to \pi_1(Y,y_0)$ is a trivial map". Here both the logic I did not understand at all.
Will someone explain me elaborately please. I am new to this subject.
Thanks for your time