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So, the maximum number 1 byte (8 bits) can have is 255, so does that mean 255 combinations of 0 & 1 in the 8 places?

Willems Leveille
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2 Answers2

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Well don't forget all zeroes. The total number of combinations is actually $2^8=256$.

J. W. Perry
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8 bits can be used to represent 256 distinct values (usually 0-255).

This is a result of the following: you have 2 choices for each bit, namely 0 or 1. When considering these choices together you are left with $2*2*2*2*2*2*2*2 = 2^8$ possible combinations of 0s and 1s.

camjuar
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