If I happen to have a two variable inequality such as $x+y<xy$ what is the most efficient way of finding out the critical points/roots since I cannot plot 3d functions in my head. For example, in the inequality, $(xy)^2<xy$, we can subtract $xy$ from both sides to get $(xy)^2-xy<0$ or $xy(xy-1)<0$, and get two cases $xy=0$ or $xy-1=0$. But sometimes the inequalities are not so clear cut. Anyone have any clues on how to tackle finding the roots of the inequality $x+y<xy$
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Hint: Can you do two isolations, one for $x$ and one for $y$? – Amzoti Nov 01 '13 at 01:56
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Hi amzoti, what do you mean by isolations? – jessica Nov 01 '13 at 02:06
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Can you write two different forms, one like $y > ...$ and another for $x > ...$ or $x < ...$, that is isolate terms on each side? – Amzoti Nov 01 '13 at 02:08
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Really sorry Amzoti, I am not understanding you. – jessica Nov 01 '13 at 03:20
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I know this is super late but I would do it like this:
x + y $\geq{xy}$
x $\geq{xy-y}$
x $\geq{y(x-1)}$
$\frac{x}{x-1}$ $\geq{y}$ or $y \leq{\frac{x}{x-1}}$
So y would be the shaded region under the graph $g(x) = \frac{x}{x-1}$
Edit: It would also contain the line
Lee Jordan
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