I don't understand this question.
The 10th organ is 4 times bigger than the 3rd organ. The amount of all 50 organs together is 3725.
Find D and a1.
How can I solve that? I have absolutely no way.
I don't understand this question.
The 10th organ is 4 times bigger than the 3rd organ. The amount of all 50 organs together is 3725.
Find D and a1.
How can I solve that? I have absolutely no way.
HINT:
Do you know if $a_1,D$ be the first term & the common difference respectively,
$n$th term $=a_1+(n-1)D$
Sum of $n$ terms $\displaystyle=\frac n2\{2a_1+(n-1)D\}$
So, you will have two equations with two unknowns
Reference : Arithmetic progression
Hint: Assuming the organs are in arithmetic progression in size, the size of organ $n$ is $a_1+d(n-1)$ Now plug in what you are given: $a_1+9d=4(a_1+2d), 50a_1+\frac 12(49)(50)d=3725$. Two equations, two unknowns.