How to find the period of the function \begin{array}{cc} e^{z}\end{array} where "z" is a complex number?? Does this function really have any period??
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rock321987
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2Yes. It has period $2\pi i$. – Hanul Jeon Nov 19 '13 at 12:19
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We say that a function $f(z)$ has period $C$ for some constant $C$ if and only if:
$$ f(z+C) = f(z) $$
for all $z$. In this case the function $e^z$ is defined in the complex plane, so it makes sense to consider complex values for $C$. In particular, since $e^{2\pi i} = 1$:
$$ e^{z+2\pi i} = e^z e^{2\pi i} = e^z $$
So the exponential function is periodic with purely imaginary period $C = 2\pi i$.
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